Thr equation of a line in Slope-Intercept form is:
![y=mx+b](https://img.qammunity.org/2023/formulas/mathematics/high-school/smsb8cbft03lwblmi49nf2l6jby2ofxzws.png)
Where "m" is the slope and "b" is the y-intercept.
You have this equation:
![2x+y=8](https://img.qammunity.org/2023/formulas/mathematics/college/sbx68my72x29fopwigw2duowzypzw00cue.png)
Solve for "y" in order to write it in Slope-Intercept form:
![y=-2x+8](https://img.qammunity.org/2023/formulas/mathematics/college/a72emo01xw23yafh4sd3ro6lobj5da8rvg.png)
You can see that the y-intercept is:
![b=8](https://img.qammunity.org/2023/formulas/mathematics/high-school/3ydwjh95g77xkxjindnxfrsd7xqy5fch1q.png)
Since "x" is zero when the line cuts the y-axis, you have this point:
![(0,8)](https://img.qammunity.org/2023/formulas/mathematics/college/y6t3sjgnrpt5tvau77z1zaq753r7v76usv.png)
You know that "y" is zero when the line cuts the x-axis. So to find the x-intercept, substitute that value of "y" into the equation and solve for "x":
![\begin{gathered} 0=-2x+8 \\ (-8)/(-2)=x \\ \\ x=4 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/j5fevm5k1gzce6blez8z3y0970zul1siuz.png)
So you also have this point:
![(4,0)](https://img.qammunity.org/2023/formulas/mathematics/college/fqwlit55gjaqab1bwwutvclxjb6poh2sqi.png)
Knowing these points, you can plot them of the Coordinate plane and graph the line.
The graph of the line is: