Let be "x" the number of classes for which the cost will be the same at both places.
According to the information given in the exercise, a person must pay $12 per class plus a starting fee of $63 in the gym We Run For Fun . Based on this, you can set up the following expression to represent this situation:
![12x+63](https://img.qammunity.org/2023/formulas/mathematics/college/ppzasxoh5oscqbaie5pkhxq4rtp2h48l2e.png)
In the gym Yoga For All there is no starting fee. A person must pay $15 per class. Then, you can set up the following expression to represent this situation:
![15x](https://img.qammunity.org/2023/formulas/mathematics/high-school/8u743w1xj5bh8y9jrdh1qn2boq7vmm04bm.png)
Since you need to find the value of "x" for which the cost will be the same, you must set up the this equation:
![12x+63=15x](https://img.qammunity.org/2023/formulas/mathematics/college/scflwznlzw9t8az4j3y1xv30vzbh0190wy.png)
Now you have to solve for "x":
![\begin{gathered} 63=15x-12x \\ 63=3x \\ \\ (63)/(3)=x \\ \\ x=21 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/e2dtlkxxrlvnnaa97nbqke8nyqu7zlnqme.png)
The answer is:
Equation:
![12x+63=15x](https://img.qammunity.org/2023/formulas/mathematics/college/scflwznlzw9t8az4j3y1xv30vzbh0190wy.png)
Number of classes:
![x=21](https://img.qammunity.org/2023/formulas/mathematics/middle-school/iqcutvq05tmaxn6yuspzp20khlvk79lgbj.png)