Question

Find the x-intercepts of y = x2 + 12x + 27.

Answer 1

Given the equation:

`y=x^2+12x+27`

We will find the x-intercepts of the function y

The x-intercept is the value of (x) when y = 0

So, we will substitute with y = 0 then solve the equation to find x

`\begin{gathered} x^2+12x+27=0 \\ \end{gathered}`

Factor the equation to find the roots:

`\begin{gathered} (x+9)(x+3)=0 \\ x+9=0\rightarrow x=-9 \\ x+3=0\rightarrow x=-3 \end{gathered}`

So, the answer will be:

The x-intercepts are the points (-9, 0) and (-3, 0)