Question

Four wires running through the corners of a square with sides of length 21.918 cm carry equal currents, 2.785 A. Calculate the magnetic field at the center of the square.

Answer 1

We will determine the magnetic field as follows:

`\begin{gathered} B=(\mu_0I)/(2r\pi) \\ \\ \Rightarrow B=((4\pi\ast10^(-7))(2.785))/(2\pi(0.21918√(2)))\Rightarrow B=1.796963578...\ast10^(-6) \\ \\ \Rightarrow B\approx1.8\ast10^(-6)T\Rightarrow B\approx1.8\mu T \end{gathered}`

So, the magnitude of the magnetic field is approximately 1.8 micro tesla.