Question

I need help on #1 B C and F G ONLY

Answer 1

Step-by-step explanation

Given that;

pH is 5

Follow the steps below

Firstly, we need to find the H^+ of the sample

`\text{ pH = -log \lparen H}^+)`

Recall, that pH is 5

`\begin{gathered} \text{ 5 = -log }\lbrack\text{ H}^+\text{ }\rbrack \\ \text{ }\lbrack\text{ H}^+\rbrack\text{ = 10}^(-5) \\ \text{ }\lbrack\text{ H}^+\rbrack\text{ = 1}*\text{ 10}^(-5)\text{ M} \end{gathered}`

Therefore, [H^+] = 1 x 10^-5 M

Find pOH?

pH + pOH = 14

pH = 5

5 + pOH = 14

subtract 5 from both sides of the equation

5 - 5 + pOH = 14 - 5

pOH = 9

Find OH^- using the below formula

`\begin{gathered} \text{ pOH = -log \lbrack OH}^-\text{ \rbrack} \\ \text{ 9 = -log \lbrack OH}^(-1)\text{ \rbrack} \\ \text{ \lbrack OH}^-\text{ \rbrack= 10}^(-9) \\ \text{ \lbrack OH}^-\text{ \rbrack= 1 }*\text{ 10}^(-9)M \end{gathered}`