The initial speed of the rocket is u = 11 m/s
The mass of the rocket is m = 1.3 kg
The kinetic energy of the rocket will be
![\begin{gathered} K\mathrm{}E\mathrm{}=(1)/(2)mu^2 \\ =78.65\text{ J} \end{gathered}](https://img.qammunity.org/2023/formulas/physics/college/uc9u6z1rfa22jhe14mpu24711filla9h4c.png)
The kinetic energy will be converted to potential energy
![KE=P\text{E}](https://img.qammunity.org/2023/formulas/physics/college/ohkxz5hrdt2nwzr875jc7hyippu132mdon.png)
Also, the potential energy will be
![PE=\text{mgh}](https://img.qammunity.org/2023/formulas/physics/college/6f5dozsxxyhd7eqfeppthprts5yaz8xuef.png)
Here, the acceleration due to gravity is g = 9.8 m/s^2
The height up to which the rocket will reach is h.
Substituting the values , the height will be
![undefined]()
78.65