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Make a table of values for the line 4x + 2y = 8. Use x = 0, for one point, y = 0 for another point, and then three other points.

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Answer:

Explanation:

To make the table of values, we first write the equation given in slope-intercept form as it is convenient.


4x+2y=8

subtracting 4x from both sides gives


2y=8-4x

then dividing both sides by 2 gives


y=(8-4x)/(2)
y=4-2x

Now we evaluate the function at x = -1, 1 , 0, 1 ,2, 3

At x = -1


\begin{gathered} y=4-2(-1) \\ \boxed{y=6} \end{gathered}

At x = 0,


\begin{gathered} y=4-2\cdot0 \\ \boxed{y=4} \end{gathered}

At x = 1


\begin{gathered} y=4-2\cdot1 \\ \boxed{y=2} \end{gathered}

At x = 2


\begin{gathered} y=4-2\cdot2 \\ \boxed{y=0} \end{gathered}

At x = 3


\begin{gathered} y=4-2\cdot3 \\ \boxed{y=-2} \end{gathered}

Hence we have the table

x | y

-1 | 6

0 | 4

1 | 2

2 | 0

3 | -2

Make a table of values for the line 4x + 2y = 8. Use x = 0, for one point, y = 0 for-example-1
User David Rhoden
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