104k views
1 vote
- Solve 2cos (3x) - 1 = 0 on the interval [0, 21).T 77 97 151 177 23T12' 12' 12' 12 12'12T7T4' 4No solutionT 137 251 111 231 35718' 18 18 '18 18 1899

User Matthijsb
by
7.8k points

1 Answer

1 vote

Let's solve the trig equation >>>


\begin{gathered} \sqrt[]{2}\cos (3x)-1=0 \\ \sqrt[]{2}\cos (3x)=1 \\ \cos (3x)=\frac{1}{\sqrt[]{2}} \\ 3x=(\pi)/(4),(7\pi)/(4) \\ x=(\pi)/(12),(7\pi)/(12) \end{gathered}

To get the other angles within 2π, we add 2π to these two angles. Thus,


undefined

User Ahmed Dhanani
by
7.7k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories