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f m∠DFC=(6b−18)°, find b so that FC−→−⊥FD−→−.I'm confused i know that its a 90 degree but i dont know where to plug the numbers
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f m∠DFC=(6b−18)°, find b so that FC−→−⊥FD−→−.I'm confused i know that its a 90 degree but i dont know where to plug the numbers

f m∠DFC=(6b−18)°, find b so that FC−→−⊥FD−→−.I'm confused i know that its a 90 degree-example-1
User Heike
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1 Answer

6 votes

Given:


\angle DFC=(6b-18)^(\circ)

FC perpendicular to FD.


\begin{gathered} \angle DFC=90^(\circ) \\ (6b-18)^(\circ)=90^(\circ) \\ 6b=90+18 \\ 6b=108 \\ b=18 \end{gathered}

User Ditoslav
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