Hello!
First, we have to solve this system, then we can classify it.
Let's solve:
![\begin{cases}4x+2y=-6 \\ 2x+y=8\end{cases}](https://img.qammunity.org/2023/formulas/mathematics/college/fys12melt0ez5n1fnsoa280mtzauvm9npu.png)
Let's isolate y in the second equation:
![y=8-2x](https://img.qammunity.org/2023/formulas/mathematics/college/nxdhfqhdryz56bghe0300il75a37lzw1o6.png)
Now, let's replace it in the first equation:
![\begin{gathered} 4x+2y=-6 \\ 4x+2\cdot(8-2x)=-6 \\ 4x+16-4x=-6 \\ \cancel{4x}+16\cancel{-4x}=-6 \\ 16=-6 \\ \text{FALSE!!!} \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/r4435y1eqv6b9gu7l4v57vunl0o4n00s4j.png)
As we can see, this linear system has no solution.
Now, let's classify it:
As this does not admit any solution, we can say that it is inconsistent.