Given the equation:

Let's find the time it takes the ball to return to the ground.
When the ball returns to the ground, the height, = 0.
Hence, to find the time it takes the ball to return to the ground, substitute 0 for h and solve for t:

Solving further:
Re-arrange the equation

Factor out -4t:

We have the individual factors:

Solve each equation for t:

For the second factor:

Therefore it will take 3.75 seconds for the ball to return to the ground.
ANSWER:
3.75 seconds