Given:
Sample of 10 students is as below
![12,15,8,9,14,8,17,14,8,15](https://img.qammunity.org/2023/formulas/mathematics/college/mbp0brx1oy6mhv73frmnhwdul7g2stq0xq.png)
Required:
We want to find the mean absolute deviation for the given sample
Step-by-step explanation:
For this,
first we need to find the mean of given sample
![(12+15+8+9+14+8+17+14+8+15)/(10)=(120)/(10)=12](https://img.qammunity.org/2023/formulas/mathematics/college/ojy0u5y0yzgl2p7xpon5f6mkmjabv1kulf.png)
Now
![\begin{gathered} \text{l12-12l=0} \\ \text{l12-15l=3} \\ \text{l12-8l=4} \\ \text{l12-9l=3} \\ \text{l12-14l=2} \\ \text{l12-8l=4} \\ \text{l12-17l=5} \\ \text{l12-14l=2} \\ \text{l12-8l=4} \\ \text{l12-15l=3} \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/34pwnllpy670g0ij6hyx1afizp661m67rt.png)
now find the mean of new sample for mean absolute deviation
![(0+3+4+3+2+4+5+2+4+3)/(10)=(30)/(10)=3](https://img.qammunity.org/2023/formulas/mathematics/college/ea7g9s5jjvvjvxj0bi2bu0ahqzo8wjlyag.png)
Final answer:
3