Question

Solve for measure of arc dg and the angle DHG

Answer 1

`\begin{gathered} FE=28\cdot2 \\ FE=56 \\ 40=(DG-FE)/(2) \\ 40\cdot2=DG-FE \\ DG=40\cdot2+FE \\ DG=40\cdot2+56 \\ DG=136 \\ \text{The value of DG is 136} \\ DHG=(DG+FE)/(2) \\ DHG=(136+58)/(2) \\ \text{DHG}=(194)/(2) \\ \text{DHG}=97 \\ \text{The value of DHG is 97} \\ \text{You cant solve the all other arcs beacuse you need to know},\text{ the } \\ \text{value of the arc }DF\text{ or }GE \end{gathered}`