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Can you please help me out with a question

User Rubixus
by
5.6k points

1 Answer

5 votes

The equation of a circle is given as


\begin{gathered} (x-h)^2+(y-k)^2=r^2 \\ \text{where h,k are the centres and h =2 while k =2} \\ x,\text{ y are the points located at P, so that x = 5 and y = 4} \\ r\text{ = radius} \end{gathered}

Substituting these values into the equation of a circle yields


\begin{gathered} (5-2)^2+(4-2)^2=r^2 \\ 3^2+2^2=r^2 \\ r^2=9+4 \\ r^2=\text{ 13} \\ r\text{ =}\sqrt[\square]{13} \\ r\text{ =3.605551275} \\ r\approx3.6\text{ units} \end{gathered}

Therefore, the answer is option A

User Leida
by
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