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In triangle ABC, ∠A=120°, a=3, and b=2. Find angle ∠C to the nearest degree.

User Gabor Angyal
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1 Answer

19 votes
19 votes

Answer:

Explanation:

Use Law of Sines to find ∠B.

∠B = arcsin(b·sinA/a) ≅ 35°

∠C = 180°-∠A-∠B = 25°

User Kjp
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