Question

Factor the equation and solve.
`{x}^(2) + 3x - 28 = 0`

Answer 1

(x+7) (x-4)

Step-by-step explanation:

x^2 + 3x - 28 = 0

a = 1

b= 3

c= -28

a x c = -28

Find two terms that added equal b, and multiplied equal c.

-4 + 7 = 3

-4 * 7 = -28

Replace the middle term:

x^2 - 4x + 7x - 28 = 0

Group and factor

(x^2 - 4x ) (7x - 28 )

x (x - 4 ) 7 (x -4)

Rewrite

(x+7) (x-4)