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If 2i is a zero of f(x)=x^4+x^2+a, find the value of a. Then find the other 3 solutions.

User GokcenG
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1 Answer

4 votes

i^4 = 1

i^2 = -1

If 2i is a zero:


(2i)^4+(2i)^2+a=0
2^4* i^4+2^2* i^2+a=0
16\text{ - 4 = a}
a=12

So the equation is going to be:


f(x)=x^4+x^2+12

User Mwaskom
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