Question

What is the standard form for g(x)= the square root of 6-x

Answer 1

The standard form of an Irrational function is given as:

`\begin{gathered} y=√(a(x-p))+q \\ \text{where:} \\ y\geqslant q\text{ and x}\geqslant p \end{gathered}`

In the given function:

`\begin{gathered} g(x)=√(6-x) \\ \text{Domain: }\left\lbrace x\in R\colon x\leqslant6\right\rbrace \\ \text{Range: }\left\lbrace y\in R,\text{ }y\geqslant0\right\rbrace \end{gathered}`

Therefore, the standard form of g(x) is:

`g(x)=√(-(x-6))`