To solve this question you have to apply the first and second derivative criteria. First we are going to derive the equation
![\begin{gathered} y^(\prime)\text{ = -28x +42} \\ \text{now we put y'=0 to find the critical points} \\ -28x\text{ +42 =0 } \\ x=(-42)/(-28)=\text{ 1.5} \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/ec95qb1g488vdd7s3xqlpnbu58f7cn4pyr.png)
Since
![y^(\doubleprime)\text{ =-28 }](https://img.qammunity.org/2023/formulas/mathematics/college/xli3v5cz5fjd1qhmuhmm2brjs9y9cdnqzp.png)
by the second derivative criteria, we know that y reaches a maximum at x=1.5. Then it takes 1.5 seconds to reach the maximum height.