Question

At Hobby Lobby, a small clock has a diameter of 20 inches a larger clock has a diameter of 34 inches. How much greater, in square inches, is the area of the larger clock than the smaller clock? Round your answer to the nearest tenth.

Answer 1

Given :

A small clock has a diameter of 20 inches.

A larger clock has a diameter of 34 inches.

The radius of the circle = r = 0.5 * the diameter (d)

So the radius of the small clock = 0.5 * 20 = 10 inches

And the radius of the larger clock = 0.5 * 34 = 17 inches

The area of the circle =

`\pi\cdot r^2`

So, the area of the small clock =

`\pi\cdot r^2=3.14\cdot10^2=3.14\cdot100=314`

And the area of the larger clock =

`\pi\cdot r^2=3.14\cdot17^2=3.14\cdot289=907.46`

The difference between the areas = 907.46 - 314 = 593.46

Rounding to the nearest tenth :

So, the area of the larger clock will 593.5 square inches more than the small clock

So, the answer is 593.5 square inches