Question

1 1 point 20 ft. Solve for x. Round to the nearest tenth of a degree.

Answer 1

26.6 degrees.​

Explanation:

A triangle diagram representing the given problem is attached below:

In the smaller right triangle:

• The side ,opposite to ,angle x = 20 ft

,

• The side ,adjacent to ,angle x = 40 ft

From trigonometric ratios:

`\begin{gathered} \tan \theta=\frac{\text{Opposite}}{\text{Adjacent}} \\ \implies\tan x\degree=(20)/(40)=0.5^{} \end{gathered}`

We then solve for x.

`\begin{gathered} x=\arctan (0.5) \\ x=26.565\degree \\ x\approx26.6\degree \end{gathered}`

The value of x is 26.6 degrees (to the nearest tenth of a degree).​