1 Answer

Joan Charmant · Answer 1 · 2023-02-17T07:56:48+0000

To determine the distance travel by the car in this motion we can use the formula:

$x-x_0=v_0t+(1)/(2)at^2_{}$

if we assume that the car starts at the origin and that the initial velocity is zero.

In this case we have that x0=0, v0=0, a=2.6 and t=14, then:

$\begin{gathered} x-0=(0)t+(1)/(2)(2.6)(14)^2 \\ x=254.8 \end{gathered}$

Therefore the car travels 254.8 meters.

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