Step-by-step explanation
Let's picture the situation described by the exercise:
We have a circle with radius r, and a (green) sector with an area of 361.6 m^2, and with a central angle of 288 degrees. To solve this exercise, we merely need to remember the formula for the area (AS) of a sector:

For we are looking for the radius, we need to solve this "equation" for the variable r:
![\begin{gathered} AS=\frac{\text{angle}}{360}\cdot\pi\cdot r^2, \\ 360\cdot AS=(\text{angle)}\cdot\pi\cdot r^2, \\ \frac{360\cdot AS}{(\text{angle)}\cdot\pi}=r^2, \\ r^2=\frac{360\cdot AS}{(\text{angle)}\cdot\pi}, \\ r=\sqrt[]{\frac{360\cdot AS}{(\text{angle)}\cdot\pi}}\text{.} \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/jubolfkg66mqdpnajtla811ysmo5lg56ym.png)
Evaluating for the values of AS and "angle" of our sector, we get
![\begin{gathered} r=\sqrt[]{\frac{360\cdot AS}{(\text{angle)}\cdot\pi}}\leftarrow\begin{cases}AS=361.6m^2 \\ angle=288 \\ \pi=3.14\end{cases}, \\ r=\sqrt[]{(360\cdot361.6m^2)/(288\cdot(3.14))}, \\ r\approx\sqrt[]{143.9m^2}, \\ r\approx11.9m. \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/dx3e89alc305j8bwi1ju2zvxr5rqfes5tb.png)
Finally, we must round up the value of r we just obtained. Note that the first decimal place (9) of 11.9 is greater than 5, then by the rounding rule we must add one tenth, to get

Answer
The radius of the circle is
