Question

A 6.7969 mol sample of C2H2 is in a 67.153 L container. What is the pressure of this gas in atmospheres at 668.44 C?

Answer 1

We will assume that the gas behaves like an ideal gas, so we can apply the following equation for ideal gases:

`PV=nRT`

Where,

P is the pressure of the gas, in atm

V is the volume of the gas in liters, 67.153L

n is the moles of the gas, 6.7969 mol

T is the temperature of the gas in Kelvin, 668.44°C=947.59K

R is a constant, 0.08206atm.L/mol.K

Now, we clear the pressure and replace the known data:

`P=(nRT)/(V)`
`P=(6.7969mol*0.08206(atm.L)/(mol.K)*947.59K)/(67.153L)=7.8206atm`

Answer: The pressure of this gas is 7.8206atm