Given:
![\begin{gathered} \text{Time Honor spent = 3}(1)/(4)\text{ hours} \\ \\ \text{Time Sequoia spent = 2}(5)/(6)\text{ hours} \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/m7e7ati9rqktimsqx5o1bna1nlh10ahorg.png)
To find how much more time Honor spent than Sequoia, subtract the amount of time Sequoia spent from that of Honor.
Therefore, we have:
First convert to simple fraction:
![\begin{gathered} 3(1)/(4)\text{ hours = }(13)/(4)\text{ hours} \\ \\ 2(5)/(6)\text{ hours = }(17)/(6)\text{ hours} \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/7iljyonpqx9j4chw0mja700heylv8vc84z.png)
Now, let's subtract:
![\begin{gathered} (13)/(4)-(17)/(6) \\ =(39-34)/(12) \\ \\ =\text{ }(5)/(12)\text{ hours} \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/5w31n6s0qbk69qe5zenhoeq3y0kyr0lq9h.png)
Therefore, Honor spent 5/12 more hours on homework than Sequoia.
ANSWER:
![(5)/(12)\text{ hours}](https://img.qammunity.org/2023/formulas/mathematics/college/8ty07tn5i07lesi6sskihb7y0a800osgl5.png)