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If 48mL of a 3.89M NH4Cl solution is diluted to 320mL, what is the concentration of the new solution?Units? SigFigs?

User Gannet
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1 Answer

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To answer to this question, we could use the following equation for dilutions:

As we know, the values provided by the problem are:

C1 = 3.89 M

V1 = 48 mL

V2 = 320 mL

C2 = ?

What we're going to do is to replace the values in the equation so we can solve for C2:

Therefore, the concentration of the new solution would be 0.58 M.

If 48mL of a 3.89M NH4Cl solution is diluted to 320mL, what is the concentration of-example-1
If 48mL of a 3.89M NH4Cl solution is diluted to 320mL, what is the concentration of-example-2
User Hermilton
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