We have to calculate the sample size in order for the margin of error to be 3.25% or less. We assume we are doing a poll for a proportion with a confidence level of 95%.
We have a formula that relates margin of error M and sample size n for a 95% confidence level:
![M=\frac{1}{\sqrt[]{n}}](https://img.qammunity.org/2023/formulas/mathematics/college/o1d6qp4hk84307bfb7pk5j4c6wy9cvbwdf.png)
NOTE: M is expressed in decimal form, not percentage.
As we know that M=0.0325, we can calculate n as:
![\begin{gathered} M=0.0325=\frac{1}{\sqrt[]{n}} \\ \sqrt[]{n}=(1)/(0.0325) \\ n=((1)/(0.0325))^2 \\ n\approx(30.77)^2 \\ n\approx946.74 \\ n=947 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/91wvbue6k2ywuakzosv200trptz8u57gy2.png)
Answer: the minimum sample size is 947 people.