Question

Help fast plz 100 points!

Answer 1

`\huge \boxed{ \boxed {\sf \: a)49 {x}^(2) + 14x + 1}}`

Explanation:

to understand this

you need to know about:

• composition of function
• PEMDAS

tips and formulas:

• 
  `(g \circ f)x \iff g(f(x))`

let's solve:

1. 
   `\sf sustitute \: the \: value \: of \: f(x) \: to \: g(x) : \\ \sf (7x + 1 {)}^(2)`
2. 
   `\sf use \: (a + b {)}^(2) = {a}^(2) + 2ab + {b}^(2) \: to \: simplify : \\ (7x {)}^(2) + 2.7x.1 + ( {1)}^(2)`
3. 
   `\sf simplify : \\ 49 {x}^(2) + 14x + 1`

Answer 2

___________________________________

`\huge\underline{\tt{\red{Problem:}}}`

• Given
  `\tt{f(x) = 7x + 1}`and
  `\tt{g(x) = {x}^(2) }`find,
  `\tt{( \: g \: \: • \ \: f \: )(x)}`.

`\huge\underline{\tt{\red{Formula:}}}`

`\tt{( \: g \: \: • \ \: f \: )(x)}`.

`\huge\underline{\tt{\red{Solution:}}}`

`\quad\quad\quad\quad \tt{ ({x}^(2) )(7x + 1)}`

`\quad\quad\quad\quad \tt{ ({x}^(2) )(7x) = 7{x}^(3) }`

`\quad\quad\quad\quad \tt{ ({x}^(2) )( 1) = {x}^(2) }`

Let's add it.

`\quad\quad\quad\quad \boxed{\tt{ {7x}^(3) + {x}^(2) }}`

`\huge\underline{\tt{\red{Answer:}}}`

`\huge \quad\quad \underline{\red{ \boxed{\tt{{7x}^(3) + {x}^(2) }}}}`

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✍︎ C.Rose❀