There are two methods for solving for x.
Method 1:
But
Therefore,
The sketch of this is shown below:
Notice that ACB forms a triangle. And we know that the sum of angles in a triangle is 180 degrees.
The angles of the triangle are:
x, 2x and 90
Therefore, we can find x using the theorem referred to above:
![\begin{gathered} x+2x+90=180\text{ (sum of angles in a triangle)} \\ 3x+90=180\text{ (Subtract 90 from both sides)} \\ 3x=180-90 \\ 3x=90\text{ (Divide both sides by 3)} \\ \\ x=(90)/(3) \\ x=30 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/tm482ch16kk38scjuk56xvfsps9px519tm.png)
Therefore, x = 30
Method 2:
The sketch of this is shown below:
Now that we have established this, we can apply the theorem that states that the sum of angles on a straight line is 180 degrees.
Thus, we can compute the value of x:
![\begin{gathered} 90+x+2x=180^0 \\ 90+3x=180 \\ \text{subtract 90 from both sides} \\ 3x=180-90 \\ 3x=90\text{ (divide both sides by 3)} \\ x=(90)/(3) \\ \\ \therefore x=30 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/x0od461x770pnp1xclh9yjjmc9b4py4vqg.png)
The answer is x = 30