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(2 √(2 + 5i)) (5 √(2 - 2i))what is the product

User Kassandra
by
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1 Answer

2 votes

Answer:


30+21i\sqrt[]{2}

Step-by-step explanation:

Let's go ahead and find the product as shown below;


(2\sqrt[]{2}+5i)(5\sqrt[]{2}-2i)
=(2\sqrt[]{2}*5\sqrt[]{2})+(2\sqrt[]{2}(-2i))+(5i*5\sqrt[]{2})+(5i*(-2i))
=(10*2)+(-4i\sqrt[]{2})+(25i\sqrt[]{2})+(-10i^2)

Note that i^2 = -1, so we'll have;


=20-4i\sqrt[]{2}+25i\sqrt[]{2}-10(-1)
\begin{gathered} =20-4i\sqrt[]{2}+25i\sqrt[]{2}+10 \\ =30+21i\sqrt[]{2} \end{gathered}

User Arun Ramachandran
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3.7k points