We will solve as follows:
In order to determie the lateral surface area and also the volume for the circular cylinder we operate as follows:
*Lateral surface area: We will determine the lateral surface area, this is the product of the circumference times the height:
![A=C\cdot h](https://img.qammunity.org/2023/formulas/mathematics/high-school/k1h4s59xzk6c8hb87p54m69h7qz1rbekx2.png)
Then:
![A=(2\pi r)\cdot h\Rightarrow A=2\pi(2)(15)](https://img.qammunity.org/2023/formulas/mathematics/high-school/8kkog41cpp695abkpg5p7vi9ym8ev95bbm.png)
![\Rightarrow A=60\pi\Rightarrow A=188.4955592](https://img.qammunity.org/2023/formulas/mathematics/high-school/xofatvb972ap22omcp26woc8ftgdgolq45.png)
![\Rightarrow A\approx188](https://img.qammunity.org/2023/formulas/mathematics/high-school/xn8kud5d742y8t61b5cb1muq3yjk4c8eq6.png)
So, the lateral surface area is approximately 188 square inches.
*Volume: We have that the volume for a circular cylinder is give by:
![V=\pi r^2h](https://img.qammunity.org/2023/formulas/mathematics/high-school/axumboiozoejyargdo4sskcbefipwsp4rb.png)
Then:
![V=\pi(2)^2(15)\Rightarrow V=60\pi](https://img.qammunity.org/2023/formulas/mathematics/high-school/7hx8b8csj8k0q0fkd7hdak3ps3gtm8en7u.png)
![\Rightarrow V\approx188](https://img.qammunity.org/2023/formulas/mathematics/high-school/b7nfnmqveznv5bdocz1td316emyiqpaiqm.png)
So, the volume of the cylinder is approxiately 188 cubic inches.