Given:
First, we determine the excluded values:
3x² - 24x - 27 = 0
3(x² - 8x - 9) = 0
3(x - 9)(x + 1) = 0
x ≠ -1 and x ≠ 9
Now we evaluate limits on -1 and 9:
So, x = 9 corresponds to a ertical asymptote
6.2m questions
8.2m answers