Let
L ----> the length
W ----> the width
The perimeter is equal to
P=2(L+W)
we have that
P=30 m ----> given
L=1.6W ---> given
substitute in the formula of perimeter
30=2(1.6W+W)
solve for W
15=2.6W
W=5.77 m
L=1.6*5.77
L=9.23 m
therefore
the dimensions are
length is 9.23 meters
width is 5.77 meters