Question

I need help please this is for my pre calculus class

Answer 1

To find the vertical asymptotes, we have to find the zeros of the denominator.

`x^2-x-2=0`

We have to find two numbers whose product is 2, and which difference is 1. Those numbers are 2 and 2.

`x^2-x-2=(x-2)(x+1)`

Then, the zeros are

`\begin{gathered} x=2 \\ x=-1 \end{gathered}`

Therefore, the vertical asymptotes are x = -1 and x = 2.