Z-score is computed as follows:
![z=(x-\mu)/(\sigma)_{}](https://img.qammunity.org/2023/formulas/mathematics/college/pwor5j6tkjldv6zh0t9ephnc4kggms1fm8.png)
where,
x: observed value
μ: mean
σ: standard deviation
Substituting with x = 166, μ = 210, and σ = 22, we get:
![\begin{gathered} z_1=(166-210)/(22)_{} \\ z_1=-2 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/rvipdog1vgibkapeo5jho0yr0jsi0fygwe.png)
Substituting with x = 254, μ = 210, and σ = 22, we get:
![\begin{gathered} z_2=(254-210)/(22)_{} \\ z_2=2 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/a55hh92ilooqculqkpvrb6xvy2ps98f1gp.png)
Now, we need to find P(-2From the above graph, P(-2This means that 95.44% of the sample is between the z-scores -2 and 2.
In the context of this problem, 50x95.44% = 47.72 ≈ 47 goldfish are expected to live between 166 and 254 days.