Let us assume that the top of the femur is circular. We would calculate the cross sectional area by applying the formula,
Area = πr^2
where
π = 3.14
r = radius
Given that diameter = 2.34,
radius = diameter/2 = 2.34/2
radius = 1.17
Cross sectional area = 3.14 x 1.17^2 = 4.298 cm^2
Given that the length = 48cm,
volume = 48 x 4.298 = 206.304 cm^3
206.304 cm^3 can support 30 times the weight of the adult. Thus,
ratio of volume to weight = 30
206.305/weight = 30
206.305 = 30 x weight
weight = 206.305/30 = 6.88
If the giant is 5 times larger than the average adult, it means that
radius of the giant's bone = 5 x 1.17 = 5.85
Area = 3.14 x 5.85 = 18.369
length of femur = 48 x 5 = 240
Volume of the giant's femur = 240 x 18.369 = 4408.56
This means that 4408.56 cm^3 should support 30 times the giants weight
Thus,
Weight of the giant = 5 times the weight of the adult
Weight of the giant = 5 x 6.88 = 34.4
Dividing the volume by the weight, we have
4408.56/34.4 = 128.15
This is more than 30
Now, the ratio of the giant's weight to the normal adult's weight should be 5. We have
146.952/6.88 = 128
This means that the femur can support up to 128 tims the weight of the giant. Since it is more than 30, then, the femur could support the giant's weight.