147k views
3 votes
Write an equation of a line that is perpendicular to y=3x+5 and contains the point (0,0).

User Mehrwolf
by
8.7k points

1 Answer

7 votes

To write the equation of a line you need to identify the slope (m) and the y-intercept (b):


y=mx+b

Slope:

Perpendicular lines have slopes that are opposite of the reciprocal of each other.

As the given line is perpendicular to y=3x+5 (slope m=3) the slope is:


\begin{gathered} \text{slope}=m \\ \\ Perpendicular\text{ slope = -}(1)/(m) \\ \\ Perpendicular\text{ slope = }-(1)/(3) \end{gathered}

Y-intercept:

Value of the line (y coordinate) when it cross the y-axis (when x is equal to 0)

As the given line contains the point (0,0) the value of y when x is 0 is also 0

y.intercept=0

Then, you get the next equation for the line:


y=-(1)/(3)x

User Ruik
by
8.1k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories