Hello, can you please help me solve this question a, b and c !

asked Sep 8, 2023 100k views

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Given:

We need to solve

$\cos ^4x-\sin ^4x$

Solution;

Now,

$\begin{gathered} \cos ^4x-\sin ^4x=(\cos ^2x)^2-(\sin ^2x)^2 \\ =(\cos ^2x-\sin ^2x)(\cos ^2x+\sin ^2x) \\ =(\cos 2x)(1) \\ =\cos 2x \end{gathered}$

So,the simpler form is

$\cos 2x$

Pshirishreddy answered Sep 14, 2023

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