Question

A car of weight W=16000N rests on a surface that is part of a hydraulic lift system. The piston below the car has an area of 4E-1m^2. An input force F is applied to another piston of the hydraulic system; this piston's area is 4E-4m^2. What input force F is necessary to lift the car?

Answer 1

In order to calculate the force required, we can use the formula below:

`(A_1)/(A_2)=(F_1)/(F_2)`

Using F1 = 16000, A1 = 4*10^-1, F2 = F and A2 = 4*10^-4, we have:

`\begin{gathered} (4\cdot10^(-1))/(4\cdot10^(-4))=(16000)/(F)\\ \\ 10^3=(16000)/(F)\\ \\ F=(16000)/(10^3)\\ \\ F=16\text{ N} \end{gathered}`

Therefore the correct option is h.