Question

The equation for the line that has a slope of -3/8 and passes through (0, 10) is: y = -3/8x + 10 : y = 3/8 x - 10

Answer 1

The standard form of expression equation of a straight line is;

`y\text{ = mx+c}`

where;

m is the slope

c is the intercept

Given

slope m = -3/8

Next is for us to get the y- intercept of the line. This is done by subtituting the slope and the point (0,10) given into the equation y = mx+c and calculating c as shown;

`\begin{gathered} y\text{ = mx+c} \\ 10\text{ = -3/8(0)+c} \\ 10\text{ = 0+c} \\ c\text{ = 10} \end{gathered}`

Next is to get the equation of the line by substituting m = -3.8 and c= 10 into the standard form of the equation as shown;

`\begin{gathered} y\text{ = mx+c} \\ y\text{ = -}(3)/(8)x+10 \end{gathered}`

Hence the first option is correct