Question

Hello, please help me with this geometry on circles and ratios.

Answer 1

To determine the tangent angle of a circle

`\begin{gathered} arcBDC\colon arcBC=3\colon2of360^0\text{ } \\ arc\text{ BDC = }(3)/(5)X360^0=216^0 \\ arc\text{ BC = }(2)/(5)x360^0=144^0 \end{gathered}`

Measure of angle A = 1/2 of arc BDC - arc BC

[tex]\begin{gathered} mHence the measure of angle 36°