Question

QUESTION 1Jim pushes on a large bookcase that has a mass of 35kg with a horizontal force of 150N. The coefficient of friction between the wooden floor and bookcaseis 0.6. If the bookcase does not move what is the magnitude of the static frictional force (from the floor) acting on the bookcase? Answer in Newtons.

Answer 1

Given data

*The given mass of the bookcase is m = 35 kg

*The given horizontal force is F = 150 N

*The coefficient of friction between the wooden floor and bookcase is

`\mu=0.6`

The formula for the magnitude of the static frictional force acting on the bookcase is given as

`\begin{gathered} F_s=\mu N \\ =\mu mg \end{gathered}`

*Here N = mg is the normal force

*Here g is the acceleration due to the gravity

Substitute the known values in the above expression as

`\begin{gathered} F_s=(0.6)(35)(9.8) \\ =205.8\text{ N} \end{gathered}`

Hence, the magnitude of the static frictional force acting on the bookcase is 205.8 N