The probability of 2 consecutive events is the product of the probabilities of the single events.
The probability (P) of a single event A is:
![P(A)=\frac{number\text{ }of\text{ }favorable\text{ }outcomes}{t=number\text{ }of\text{ total }outcomes}](https://img.qammunity.org/2023/formulas/mathematics/college/rsmqgfq02eanerbcsqal16f7o7l2sohp2h.png)
So, let's find the probability of the first event:
Event: Landing on a number less than 6.
Number of Favorable outcomes: 2 (Landing on 6 or 7).
Total outcomes: 3 (Landing on 6, 7, or 8).
Then,
![P(A)=(2)/(3)](https://img.qammunity.org/2023/formulas/mathematics/college/zf40ahyg2j8pu9m4l1mckn99hutde9vvs2.png)
Now, let's find the probability of the second outcome:
Number of Favorable outcomes: 1 (Landing on 6 ).
Total outcomes: 3 (Landing on 6, 7, or 8).
![P(B)=(1)/(3)](https://img.qammunity.org/2023/formulas/mathematics/college/qvceqfs09rx6wgihc8b3cazruyl3cuuh1s.png)
Then, the probability of landing on a number less than eight and then landing on a 6 is:
![\begin{gathered} P=P(A)*P(B) \\ P=(2)/(3)*(1)/(3) \\ P=(2)/(9) \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/t07i4lonojq7o3xrff69tbf87bnpesdpmj.png)
Answer: 2/9.