Question

Someone help me with this question..this is a practice question

Answer 1

68

Step-by-step explanation:

We start with the mode:

`\text{Mode}=l+((f_1-f_0)* h)/((2f_1-f_0-f_2))`

Where the terms are defined as follows:

`\begin{gathered} l=\text{lower limit of the modal class} \\ f_1=\text{frequency of the modal class} \\ f_0=\text{frequency of the class before the modal class} \\ f_2=\text{frequency of the class after the modal class} \\ h=\text{size of the class interval} \end{gathered}`

From the table, the modal class is 65-69.

Therefore:

`\begin{gathered} l=\text{6}5 \\ f_1=\text{1}9 \\ f_0=\text{1}0 \\ f_2=\text{1}3 \\ h=\text{5} \end{gathered}`

We substitute into the formula:

`\begin{gathered} \text{Mode}=65+((19-10)*5)/((2*19-10-13)) \\ =65+(9*5)/(15) \\ =65+(45)/(15) \\ =65+3 \\ =68 \end{gathered}`

The mode of the given data is 68.