Question

The Verticles of a rectangle are located at (1,2) (5,0) (2,-6) and (-2,-4) what is the area of the rectangle

Answer 1

The area of the rectangle is given by:

`A=B\cdot H`

Where:

B = Base

H = Height

Let's find B and H using the distance formula:

`\begin{gathered} B=\sqrt[\square]{(-2-2)^2+(-4-(-6))^2} \\ B=\sqrt[\square]{16+4} \\ B=\sqrt[]{20} \end{gathered}`
`\begin{gathered} H=\sqrt[\square]{(5-2)^2+(0-(-6))^2} \\ H=\sqrt[\square]{9+36} \\ H=\sqrt[]{45} \end{gathered}`

Therefore:

`\begin{gathered} A=\sqrt[]{20}\cdot\sqrt[]{45} \\ A=30 \end{gathered}`