Given data:
Frequency of fundamental harmonics, f = 196 Hz
Length of string, L = 0.34 m
Linear mass density of string,

Formula of frequency of standing wave on a string is as follows:
![f_1=\frac{\sqrt[]{(T)/(\mu)}}{2L}](https://img.qammunity.org/2023/formulas/physics/college/4zzda0qf9dlvu81ho2r0qyss7gse3oyuho.png)
Substitute given values in above equation,
![196=\frac{\sqrt[]{(T)/(4*10^(-3))}}{2*0.34}](https://img.qammunity.org/2023/formulas/physics/college/xlgp6ck3vw95sr3tvbqixu7xwa7q40ovkw.png)
Taking square of above equation,

Formula of velocity is as follows:
![v=\sqrt[]{(T)/(\mu)}](https://img.qammunity.org/2023/formulas/physics/college/jo1j3v4x76a06q1inj4lx6zngorhv0l2iu.png)
Here, T is tension
Substitute known values in above equation,
![\begin{gathered} v=\sqrt[]{(208.98)/(4*10^(-3))} \\ v=\sqrt[]{52245} \\ v=228.57\text{ m/s} \end{gathered}](https://img.qammunity.org/2023/formulas/physics/college/gqkhfx6r99mcbvp5mslro1zwldk4fvlpn1.png)
Formula of frequency of nth harmonics is as follows:

Now, In the given case,
we have to find frequency of first three harmonics
Frequency of fundamental harmonics is given.
Hence,
Frequency of second harmonics is as follows:
Substitute values of frequency fundamental harmonics in above equation,

Frequency of third harmonics is as follows:
