![r+3=-5+3r](https://img.qammunity.org/2023/formulas/mathematics/high-school/klyvhz9l8zjxfe2i71p62f7631fq3bpco2.png)
To solve for r, the objective is to isolate the variable on one side of the equation and all other terms on the other side.
- First, pass "3" to the right side of the equation by applying the opposite operation "-3" to both sides of the equal sign:
![\begin{gathered} r+3-3=-5-3+3r \\ r=-8+3r \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/high-school/fa06zq7bv1spa3s6fcdrw7313unj4rt4dh.png)
-Second, pass "3r" to the left side of the equation by applying the opposite operation "-3r" to both sides of it:
![\begin{gathered} r-3r=-8+3r-3r \\ -2r=-8 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/high-school/gp06exd3ffwirlw00x2cw5oijb0e33ur6l.png)
Third, the variable is being multiplied by "-2", to cancel this multiplication you have to apply the opposite operation, that is, divide the term by -2. And to keep the equality valid, you have to divide both sides.
![\begin{gathered} (-2r)/(-2)=(-8)/(-2) \\ r=4 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/high-school/8nap1240ywq9wr5tbc9iqvn1iw2wuxl6qa.png)
The result is r=4.