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Mary has been getting up extra early on school days so far she has woken up 6 out of 80 school days what percent of the days has she get been getting up early

User Marjeta
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1 Answer

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Let's begin by identifying key information given to us:

Number of times she woke early (e) = 6

Total number of days (t) = 80 days

The percentage of days she's been getting up early ​is given by:


\begin{gathered} \text{\%}n\text{=}(e)/(t)\cdot100\text{\%} \\ \text{\%}n=(6)/(80)\cdot100\text{\%} \\ \text{\%}n=7.5\text{\%} \end{gathered}

Mary has gotten up early 7.5% of the days

User Kenny Body
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