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Complete SquareEquation in (x+a)^2=b3x^2-18x= 357

User SEGV
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1 Answer

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3x^2-18x=357

the coefficiont of x2 must be 1, so divide the equation by 3


x^2-6x=119

take half the coefficient of x and squared


\begin{gathered} (-6)/(2)=-3 \\ \\ (-3)^2=9 \end{gathered}

then, add to both sides


x^2-6x+9=119+9

Now we can rewrite the left side of the equation as a square term.


\begin{gathered} (x-3)^2=128 \\ \end{gathered}

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