Question

Complete SquareEquation in (x+a)^2=b3x^2-18x= 357

Answer 1

`3x^2-18x=357`

the coefficiont of x2 must be 1, so divide the equation by 3

`x^2-6x=119`

take half the coefficient of x and squared

`\begin{gathered} (-6)/(2)=-3 \\ \\ (-3)^2=9 \end{gathered}`

then, add to both sides

`x^2-6x+9=119+9`

Now we can rewrite the left side of the equation as a square term.

`\begin{gathered} (x-3)^2=128 \\ \end{gathered}`