Question

A 1.2 KG rubber ball is being thrown in the air if the ball is traveling at 2.0 M/S when it is 3.0 M off the ground what is the total energy

Answer 1

Explanation:

We have that the total energy is given by the following formula:

`\begin{gathered} E_T=E_C+E_P \\ E_C=(1)/(2)\cdot m\cdot v^2 \\ E_P=m\cdot g\cdot h \end{gathered}`

We replace and calculate the total value of the energy: